public class PipeClonerImpl extends PipeCloner
Since Pipe
s may form an arbitrary directed graph, someone needs
to keep track of isomorphism for a clone to happen correctly. This class
serves that role.
master2copy
Modifier | Constructor and Description |
---|---|
|
PipeClonerImpl() |
protected |
PipeClonerImpl(Map<Object,Object> master2copy) |
Modifier and Type | Method and Description |
---|---|
void |
add(AbstractTubeImpl original,
AbstractTubeImpl copy)
Disambiguation version.
|
void |
add(Pipe original,
Pipe copy)
The
Pipe version of add(Tube, Tube) . |
void |
add(Tube original,
Tube copy)
This method must be called from within the copy constructor
to notify that the copy was created.
|
<T extends Pipe> |
copy(T p)
Pipe version of copy(Tube) |
<T extends Tube> |
copy(T t)
Invoked by a
Tube.copy(com.sun.xml.ws.api.pipe.TubeCloner) implementation
to copy a reference to another pipe. |
clone
clone
public <T extends Pipe> T copy(T p)
Pipe
version of copy(Tube)
copy
in class PipeCloner
public void add(Pipe original, Pipe copy)
Pipe
version of add(Tube, Tube)
.add
in class PipeCloner
public void add(AbstractTubeImpl original, AbstractTubeImpl copy)
public void add(Tube original, Tube copy)
TubeCloner
When your pipe has references to other pipes, it's particularly important to call this method before you start copying the pipes you refer to, or else there's a chance of inifinite loop.
add
in class TubeCloner
public <T extends Tube> T copy(T t)
TubeCloner
Tube.copy(com.sun.xml.ws.api.pipe.TubeCloner)
implementation
to copy a reference to another pipe.
This method is for Tube
implementations, not for users.
If the given tube is already copied for this cloning episode, this method simply returns that reference. Otherwise it copies a tube, make a note, and returns a copied tube. This additional step ensures that a graph is cloned isomorphically correctly.
(Think about what happens when a graph is A->B, A->C, B->D, and C->D if you don't have this step.)
copy
in class TubeCloner
t
- The tube to be copied.Copyright © 2015 Oracle Corporation. All rights reserved.